# Specific Heat Capacity Coursework Physics Gcse Formula

The specific heat capacity of a substance is the amount of heat required to raise one gram of the substance by one degree Celsius. Water, for example, has a specific heat capacity of 4.18 . This means to heat one gram of water by one degree Celsius, it would require 4.18 joules of energy.

s = specific heat capacity (sometimes represented by the letter c, or C_{s})

q = heat

m = mass

Δ T = change in temperature

Specific Heat Capacity Formula Questions:

1. What is the specific heat capacity of iron if it takes 125 J of heat to raise 111 grams by 2.5 degrees Celsius?

Answer:

2. What is the specific heat capacity of aluminum if it takes 2500 J to raise 150 grams from 10°C to 28.5°C?

Answer:

In this problem the change in temperature must be determined by taking the final temperature (T_{f}) minus the initial temperature (T_{i}).

Δ T = T_{f} - T_{i}

Δ T = 28.5°C – 10°C

Δ T = 18.5°C

Continue by solving the equation for specific heat capacity.

When the temperature of an object increases it has gained energy. The amount of energy depends on:

- The temperature change, θ
- The mass of the object, m
- The specific heat capacity, c

The **specific heat capacity** is different for different materials. It is the energy needed to increase the temperature of 1 kg of the material by 1°C and is measured in J/kg °C.

**Energy = mass × specific heat capacity × temperature change E = m × c × θ**

**Build Your Understanding** - This is how to measure the specific heat capacity of a metal block:

*Measure the temperature and the mass of the block, m.**Use an electric heater to raise the temperature of a metal block. Energy supplied,***E = power × time.***Measure the temperature of the block at the end of the heating time and calculate the increase in temperature θ.**Calculate the specific heat capacity of the metal,*

*c = E m × θ*

The video below explains more about specific heat capacity

## 0 Replies to “Specific Heat Capacity Coursework Physics Gcse Formula”